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[linux-dvb] Re: Weird problem



Hello Klaus,

4*4*8 = 256.

Strange... on my calculator 4*4*8 results in 128...
Just a note, don't mean to be the wise guy here.
Smart ass ;-)

Actually there are nine possible devices for each adapter
("video", "audio", "sec", "frontend", "demux", "dvr", "ca", "net", "osd"), so we need 4 bits to encode them, not 3.

So we have 4 adapters * (4 * 16 devices) = 256.

Klaus
CU
Michael.



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